If earth suddenly stops revolving and whole of its K.E. is used up for raising its temperature and if S = specific heat, R = radius, `omega` = angular velocity of earth, the rise of temperature of earth is : (J = joules constant)

Options

A. `(R^(2)omega^(2))/(5S)`
B. `(R^(2)omega^(2))/(5J)`
C. `(R^(2)omega^(2))/(5JS)`
D. `(R^(2)omega)/(5JS)`

Answer

C

Explanation

Here `MStheta=(1)/(2)xx(2)/(5)(MR^(2)omega^(2))/(J)`
`therefore theta=(R^(2)omega^(2))/(5JS)`