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A thin circular ring of mass m and r is ...

A thin circular ring of mass m and r is rotating about its axis with a constant angular velocity `omega`. Two objects, each of mass m are attached gently to the opposite ends of a diameter of the ring wheel now rotates with an angular velocity :

A

`omegaM//(M+m)`

B

`omega(M-2m)//(M+2m)`

C

`omegaM//(M+2m)`

D

`omega(M+2m)//M`

Text Solution

Verified by Experts

The correct Answer is:
C

`I_(1)omega_(1)=I_(2)omega_(2)impliesMr^(2)omega=(Mr^(2)+mr^(2)+mr^(2))omega_(2)`
`omega_(2)=(Momega)/(M+2m)`
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