A constant couple of 500 Nm turns a wheel of moment of inertia 100 kg `m^(2)` about an axis through its centre, the angular velocity gained in two second is :

Options

A. 5 rad `s^(-1)`
B. `100ms^(-1)`
C. `200ms^(-1)`
D. 10 rad `s^(-1)`

Answer

D

Explanation

`alpha=(tau)/(I)=(500)/(100)=5" rad/"s^(2)`
`omega=omega_(0)+alphat.=0+5xx2=10" rad/s"`