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A ring rolls on a plane surface. The fra...

A ring rolls on a plane surface. The fraction of total energy associated with its rotation is :

A

`(1)/(2)`

B

1

C

`(1)/(4)`

D

`(2)/(1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`T.E.=(1)/(2)mv^(2)+(1)/(2)Iomega^(2)=(1)/(2)mv^(2)+(1)/(2)mr^(2)omega^(2)`
`=(1)/(2)mv^(2)+(1)/(2)mv^(2)=mv^(2)`
`therefore (E_("rotational"))/(E_("total"))=((1)/(2)mv^(2))/(mv^(2))=(1)/(2)`
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Knowledge Check

  • A ring rolls down an inclined plane. At the bottom its kinetic energy is E. Theratio of its rotational K.E. to the translational K.E. is :

    A
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    B
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    D
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  • When a sphere of moment of inertia I moves down an inclined plane, the percentage of energy which is rotational, is approximately :

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    B
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    C
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    D
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  • When a sphere of moment of inertia I moves down an inclined plane, the percentage of energy which is rotational, is approximately :

    A
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    B
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