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A ring is rotating without slipping. The...

A ring is rotating without slipping. The ratio of its translational kinetic energy to the total K.E. is :

A

`1:2`

B

`2:3`

C

`3:2`

D

`2:1`

Text Solution

Verified by Experts

The correct Answer is:
A
Total K.E. = `(1)/(2)mv^(2)+(1)/(2)Iomega^(2)=(1)/(2)mv^(2)+(1)/(2)mpi^(2)omega^(2)`
= `(1)/(2)mv^(2)+(1)/(2)mv^(2)=mv^(2)`
`therefore (E_("trans"))/(E_("total"))=((1)/(2)mv^(2))/(mv^(2))=(1)/(2)`
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