The moment of inertia of a solid sphere of mass M and radius R, about an axis through its centre, is `(2)/(5)MR^(2)`. The moment of inertia about an axis tangential to the surface of the sphere will be :

Options

A. `(4)/(5)MR^(2)`
B. `(6)/(5)MR^(2)`
C. `(7)/(5)MR^(2)`
D. `MR^(2)`

Answer

C

Explanation

`I_(T)=I_(C)+MR^(2)=(2)/(5)MR^(2)+MR^(2)=(7)/(5)MR^(2)`