The moment of inertia of a uniform circular disc of mass M and radius R about any of its diameter is `(1)/(4)MR^(2)`. What is the moment of inertia of the disc about an axis passing through its centre and normal to the disc?

Options

A. `MR^(2)`
B. `2MR^(2)`
C. `(3)/(2)MR^(2)`
D. `(1)/(2)MR^(2)`

Answer

D

Explanation

By theorem of `_|_` axis
`I_(Z Z.)=I_(AB)+I_(CD)=(1)/(4)MR^(2)+(1)/(4)MR^(2)`

`I_(Z Z.)=(1)/(2)MR^(2)`