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A flywheel of moment of inertia 250 kg m...

A flywheel of moment of inertia `250 kg m^(2)` is rotating at an angular speed of 12 rad `s^(-1)`. What torque is needed to stop the wheel in 6 s ?

A

500 Nm

B

1000 Nm

C

1500 Nm

D

2000 Nm

Text Solution

Verified by Experts

The correct Answer is:
A
`omega_(2)=12" rad/s, "omega=0,t=6s`
`therefore alpha=(omega-omega_(0))/(t)=(0-12)/(6)=-2" rad/"s^(2)`
`therefore` retardation = `2" rad/"s^(2)`
`therefore` Retarding torque, `tau=Ialpha=250xx2=500Nm`
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