A uniform disc of mass m and radius r rotates about frictionless axle passing through its centre and perpendicular to its plane. A chord is wound over the rim of the disc. A uniform force F is applied to the other end of chord. The tangential acceleration is proportional to :

Options

A. `R^(1)`
B. `R^(-1)`
C. `R^(-2)`
D. `R^(0)`

Answer

D

Explanation

Here `I.alpha=Fr`
`alpha=(Fr)/((1)/(2)Mr^(2))=(2F)/(r.M)`
`r.alpha=a=(2F)/(M)` = constant.