Home
Class 12
PHYSICS
The moment of Inertia of a uniform semic...

The moment of Inertia of a uniform semicircular disc of mass M and radius 'r' about a line perpendicular to the plane of the disc through the centre is :

A

`(1)/(4)Mr^(2)`

B

`(2)/(5)Mr^(2)`

C

`Mr^(2)`

D

`(1)/(2)Mr^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
MI of full disc of double mass is `I=((1)/(2)2Mr^(2))=Mr^(2)`
implies MI of given half disc is `I.=(1)/(2)(Mr^(2))=(1)/(2)Mr^(2)`
Promotional Banner

Topper's Solved these Questions

  • ROTATIONAL MOTION

    MODERN PUBLICATION|Exercise LEVEL-II (MCQ)|74 Videos

  • ROTATIONAL MOTION

    MODERN PUBLICATION|Exercise LEVEL-III (MCQ)|10 Videos

  • RAY OPTICS

    MODERN PUBLICATION|Exercise RECENT COMPETITIVE QUESTION|32 Videos

  • SOLIDS & SEMICONDUCTOR DEVICES

    MODERN PUBLICATION|Exercise Revision Test|28 Videos

Similar Questions

Explore conceptually related problems

The moment of inertia of a circular ring of radius r and mass M about diameter is

The moment of inertia of a circular disc of radius 2m and mass 1 kg about an axis passing through the centre of mass but perpendicular to the plane of the disc is 2" kg m"^(2) . Its moment of inertia about an axis parallel to this axis but passing through the edge of the disc is . . . . . . . . . . (See the given figure)

What is the moment of inertia of a rod of mass M, length l about an axis perpendicular to it through one end?

What is the radius of gyration for a thin about an axis perpendicular to the length and axis passing through the midpoint of the rod ?