Home
Class 12
PHYSICS
A round uniform body of radius R, mass M...

A round uniform body of radius R, mass M and moment of inertia 'I', rolls down (without slipping) an inclined plane making an angle `theta` with the horizontal. Then its acceleration is :

A

`(gsintheta)/(1+MR^(2)//I)`

B

`(gsintheta)/(1-I//MR^(2))`

C

`(gsintheta)/(1+MR^(2)//I)`

D

`(gsintheta)/(1+I//MR^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
the acceleration of rolling body is :
`a=(gsintheta)/(1+(I)/(MR^(2)))`
Promotional Banner

Topper's Solved these Questions

  • ROTATIONAL MOTION

    MODERN PUBLICATION|Exercise LEVEL-II (MCQ)|74 Videos

  • ROTATIONAL MOTION

    MODERN PUBLICATION|Exercise LEVEL-III (MCQ)|10 Videos

  • RAY OPTICS

    MODERN PUBLICATION|Exercise RECENT COMPETITIVE QUESTION|32 Videos

  • SOLIDS & SEMICONDUCTOR DEVICES

    MODERN PUBLICATION|Exercise Revision Test|28 Videos

Similar Questions

Explore conceptually related problems

The minimum force required to start pushing a body up a rough (frictional coefficient ) inclined plane is F_(1) while the minimum force needed to prevent it from sliding down is F_(2) if the inclined plane makes an angle theta with the horizontal such that theta = 2mu then the ratio F_(1)//F_(2) is :

A body of mass 2 kg rests on a rough inclined plane making an angle of 30^(@) with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is :

A solid sphere of mass m rolls down an inclined plane without slipping from rest at the top of an inclined plane.The linear speed of the sphere at the bottom of the inclined plane is v .The kinetic energy of the sphere at the bottom is