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A thin uniform rod of length l and massm...

A thin uniform rod of length l and massm is swinging freely about a horizontal axis passing through its end. It maximum angular speed is `omega`. Its centre of mass rises to a maximum height of :

A

`(1)/(2)(l^(2)omega^(2))/(g)`

B

`(1)/(6)(l^(2)omega^(2))/(g)`

C

`(1)/(3)(l^(2)omega^(2))/(g)`

D

`(1)/(6)(lomega)/(g)`

Text Solution

Verified by Experts

The correct Answer is:
B
Here K.E. of rotation = P.E.
`(1)/(2)Iomega^(2)=mgh`
`(1)/(2)xx(1)/(3)ml^(2)omega^(2)=mgh`
implies `h=(l^(2)omega^(2))/(6g)`
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