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A force vec(F)=5 hat(i)+2hat(j)-5hat(k) ...

A force `vec(F)=5 hat(i)+2hat(j)-5hat(k)` acts on a particle whose position vector is `vec(r)=hat(i)-2hat(j)+hat(k)`. What is the torque about the origin ?

A

`8hati+10hatj+12hatk`

B

`8hati+10hatj-12hatk`

C

`8hati-10hatj-8hatk`

D

`10hati-10hatj-hatk`

Text Solution

Verified by Experts

The correct Answer is:
A

`vectau=vecrxxvecF=(hati-2hatj+hatk)xx(5hati+2hatj-5hatk)`
`=|(hati,hatj,hatk),(1,-2,1),(5,2,-5)|=hati(10-2)-hatj(-5-5)+hatk(2+10)`
`vectau=8hati+10hatj+12hatk`
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