One end of a uniform bar of weight `W_(1)` is clamped to the ceiling and a weight `W_(2)` is suspended to the other end. If the area of cross-section is A, what is the stress at the mid-point of the rod ?

Options

A. `(W_(1)+W_(2))/A`
B. `(W_(1)-W_(2))/A`
C. `((W_(1))/2+W_(2))/A`
D. `((W_(2))/2+W_(1))/A`

Answer

C

Explanation

Stress=`("Weight" W_(2) + "Half the wt. of rod")/("area")`
`=(W_(2)+(W_(1))/2)/A`
Correct Choice is (c).