A capillary tube is attached horizontally to a constant head arrangement. If the radius of the capillary tube is increased by 10%, the rate of flow of liquid changes by:

Options

A. `+10%`
B. `+46%`
C. `-10%`
D. `-46%`

Answer

B

Explanation

Here R =`(8etal)/(pir^(4))` Let initial liquid flow = C
Then Pressure difference P = CR …(i)
Resistance `R.=(8etal)/(pi((110r)/100)^(4))`
`=(100/110)^(4)((8etal)/(pir^(4)))`
`thereforeR/(R.)=(110/100)^(4)=(1.1)^(4)=1.4641`
`C.R.=CR`
`(C.)/CR/(R.)=1.4641`
`therefore%` age increase= (1.46-1) `xx` 100 = + 46%
`therefore` Correct choice is (b).