A gas is filled in container at pressure `P_(0)`. If the mass of molecules is halved and their rms speed is doubled, then the resultant pressure would be :

Options

A. `2P_(0)`
B. `4P_(0)`
C. `(P_(0))/4`
D. `(P_(0))/2`

Answer

A

Explanation

Using, `P=1/3Pv_("rms")^(2)=1/3(mN)/VV_("rms")^(2)`
`thereforePpropmv_("rms")^(2)`
As mis halved `v_("rms")` is doubled P becomes twice= `2P_(0)`.
Correct choice is (a)