Pressure inside two soap bubbles are 1.01 and 1.02 atmosphere. Ratio between their volumes is :

Options

A. `102:101`
B. `(102)^(3):(103)^(3)`
C. `8:1`
D. `2:1`

Answer

C

Explanation

`P_(i)-P_(0)=(4T)/(R_(1))`
`rArrR_(1)=(4T)/(1.01-1)=(4T)/(0.01)`
Similarly for second bubble,
`R_(2)=(4T)/(1.02-1)=(4T)/(0.02)`
Now `(R_(1))/(R_(2))=(0.02)/(0.01)=2`
`therefore(V_(1))/(V_(2))=((R_(1))/(R_(2)))^(3)=8`
Hence the correct choice is (c).