Spheres of iron and lead having same mass are completely immersed in water. Density of lead is more than that of iron. Apparent loss of weight is `W_(1)` for iron sphere and `W_(2)` for lead sphere. Then `(W_(1))/(W_(2))` is :

Options

A. 1
B. between 0 and 1
C. 0
D. `gt1`

Answer

D

Explanation

Mass of iron sphere = mass of lead sphere
`m_(1)=m_(2)`
`V_(1)p_(1)=V_(2)p_(2)`
`(V_(1))/(V_(2))=(p_(2))/(p_(1))rArrprop1/p`
Since density of iron is less than density of lead.
`therefore` Iron sphere has more volume and will displace more water. Now apparent loss of weight is equal to weight of water displaced. So apparent loss of weight `W_(1)` for iron is more than loss of wt. `W_(2)` for lead.
`therefore(W_(1))/(W_(2))gt1`
So correct choice is (d).