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Under a constant pressure head, the rate...

Under a constant pressure head, the rate of flow of orderly volume flow of liquid through a capillary tube is V, if the length of the capillary is doubled and the diameter of the bore is halved, the rate of flow would become

A

`V//4`

B

`V//8`

C

16V

D

V/32

Text Solution

Verified by Experts

The correct Answer is:
D
Rate of flow of liquid is V =`(pipr^(4))/(8etal)`
`thereforeVprop(r^(4))/l`
since diameter is halved so radius is also halved. Also length is doubled.
`thereforeV.` becomes `1/32` times V
So correct choice is (d).
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