A man standing symertrically between parallel cliffs, claps his hands and hearing a series of echoes at intervals of s if speed of sound in air is 340 m/s then the distance between two parallel cliffs is :

Options

A. 340 m
B. 510 m
C. 680 m
D. 270 m .

Answer

A

Explanation

here `(2x)/(v) = 1 ` sec
x = `(v)/(2) = (340)/(2) = 170 `m.
`therefore` distance between two cliffs = `2xx 170 = 340 `m.
Hence the correct choice is (a).