Velocity of sound in air is 300 m/s. Then the distance between two successive nodes of a stationary wave of frequency 1000 Hz is :

Options

A. 10 cm
B. 20 cm
C. 15 cm
D. 30 cm

Answer

C

Explanation

v = 300 `ms^(-1), " " v = 1000` hz.
`lambda = (u)/(v) = (300)/(1000) = 0.3` m
`lambda` = 30 cm Now distance between two consecutive nodes is x = `(lambda)/(2) ` .
x = `(30)/(2) = 15` cm
Hence the correct chioce is (c).