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A stationary sound wave has frequency 16...

A stationary sound wave has frequency 165 Hz (speed of sound in air = 330 m/s), then distance between two consecutive nodes is :

A

2 m

B

0.5 m

C

1 m

D

4 m

Text Solution

Verified by Experts

The correct Answer is:
C
Wavelength `lambda = (u)/(v) = (330)/(165) = 2m`
distance between two consecutive nodes = `(lambda)/(2) ` = 1m
thus correct choice is (C).
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