When two progressive waves `y_(1)` = 4 sin (2x - 6t) and `y_(2) = 3 sin (2x -6t - (pi)/(2))` are superimposed, the amplitude of the resultant wave is ............. .

Options

A. 5 m
B. 10 m
C. 20 m
D. 40 m

Answer

B

Explanation

since `Delta phi = pi//2` ,
`A_("resultant ") = (A_(1)^(2) + A_(2)^(2) + 2A_(1) A_(2) cos Delta phi )^(1//2) `
=` sqrt((4)^(2) + (3)^(2))` = 5
So, correct choice is (b) .