The velocity of sound in gas in which two waves of wavelength 1.0 m and 1.01 m produces 4 beats/s is :

Options

A. 360 m/s
B. 404 m/s
C. 1010 m/s
D. 440 m/s

Answer

B

Explanation

`v_(1) = (v)/(lambda_(1)) = (v)/(1) and v_(2) = (v)/(lambda_(2)) = (v)/(1.01) `
Now `b = v_(1) - v_(2) = (v)/(1) = (v)/(1.01) `
4 = v `[ 1 - (1)/(1.01) ] `
`rArr " " v = 404 ms^(-1)` .
Hence the correct choice is (b).