Standing waves are produced in a 10 m long stretched string. If the string vibrates in 5 segments and the wave velocity is 20 m/s, the frequency is :

Options

A. 2 Hz
B. 4 Hz
C. 5 Hz
D. 10 Hz

Answer

C

Explanation

l = 10 m , distance between two nodes
`= (10)/(5) ` = 2m
`therefore (lambda)/(2) = 2m or lambda = 4m`
v = 20 `ms^(-1)`
`therefore n = (v)/(lambda) = (20)/(4) ` = 5 Hz.
correct choice is (C).