If the tension and diameter of a sonometer wire of fundamental frequency vare doubled and density is halved, then its fundamental frequency will become

Options

A. v/4
B. v
C. `sqrt(2)` v
D. v/`sqrt(2)`

Answer

B

Explanation

n = `(1)/(2l ) sqrt((T)/(m)) = (1)/(2l ) sqrt((T)/(pi r^(2).rho)) `
Since tension and diameter both are doubled, so frequency remains the same.
Correct chocie is b.