A black body at high temperature T K radiates energy at the rate `"E W / m"^(2)`. When the temperature falls to `((T)/(2))` K, the radiated energy will be :

Options

A. `E//4`
B. `E//8`
C. `2E`
D. `E//16`

Answer

D

Explanation

`(E_(2))/(E_(1))=((T_(2))/(T_(1)))^(4)" "rArr(E_(2))/(E_(1))=((T//2)/(T))^(2)`
`rArrE_(2)=(E)/(16)`
Thus correct choice is (d).