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The ratio of energy of emitted radiation...

The ratio of energy of emitted radiation of a black body at `27^(@)C` and `927^(@)C` is :

A

`1:4`

B

`1:16`

C

`1:64`

D

`1:256`

Text Solution

Verified by Experts

The correct Answer is:
D
`(E_(1))/(E_(2))=((T_(1))/(T_(2)))^(4)=((27+273)/(927+273))^(4)`
`(E_(1))/(E_(2))=((1)/(4))^(4)" "rArr(E_(1))/(E_(2))=(1)/(256)`
Thus correct choice is (d).
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