Energy is being emitted from the surface of a black body at `127^(@)C` temperature at `1xx10^(6)" J s"^(-1)"m"^(-2)`. Temperature of the black body at which the rate of emission is `16xx10^(6)"J s"^(-1)"m"^(-2)` will be :

Options

A. `254^(@)C`
B. `508^(@)C`
C. `527^(@)C`
D. `272^(@)C`.

Answer

C

Explanation

`(E_(2))/(E_(1))=((T_(2))/(T_(1)))^(4)`
`(16xx10^(6))/(1xx10^(6))=((T_(2))/(400))`
`2=((T_(2))/(400))rArrT_(2)=800K=527^(@)C`
Thus correct choice is (c ).