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A dip circle lies initially in the magne...

A dip circle lies initially in the magnetic meridian if it is now rotated through angle `theta` in the horizontal plane then tangent of the angle of dip is changed in the ratio

A

`(tan Phi)/(tan Phi)=(1)/(sin theta)`

B

`(tan Phi)/(tan Phi)=(1)/(cos theta)`

C

`(tan Phi)/(tan Phi)=(1)/(tan theta)`

D

`(tan Phi)/(tan Phi)=(1)/(cot theta)`

Text Solution

Verified by Experts

The correct Answer is:
B
Let `Phi` =angle of the dip
`therefore tan Phi =(V)/(H)`
then tan `Phi=(V)/(H)=(V)/(H cos theta)`
Then `(tan Phi)/(tan Phi)=(1)/(cos theta)`
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