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Two like poles of strength m(1) and m(2)...

Two like poles of strength `m_(1)` and `m_(2)` are far distance apart the energy required to bring them `r_(0)` distance apart is

A

`(mu_(0))/(4pi)(m_(1)m_(2))/(r_(0))`

B

`(mu_(0))/(8pi)(m_(1)m_(2))/(r_(0))`

C

0

D

`(mu_(0))/(4pi)(m_(1)m_(2))/(r_(0))`

Text Solution

Verified by Experts

The correct Answer is:
A
`W=triangle U =U_(2)-U_(1)`
`=(mu_(0)m_(1)m_(2))/(4pir_(0))-0=(mu_(0)m_(1)m_(2))/(4pir_(0))`
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