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A straight wire carrying current I is tu...

A straight wire carrying current I is turned into circular loop if the magnitude of magnetic moment associated with it in is m the length of wire will be

A

`4piimn`

B

`sqrt {(4pim)/(i)}`

C

`sqrt(4pii)/(m)`

D

`(mpi)/(4i)`

Text Solution

Verified by Experts

The correct Answer is:
B
Magnetic of magnet =10 cm `=10xx10^(-2)m`
`r=15xx10^(-2) m`
`OP=sqrt(225-25)=sqrt(200)` cm
since at the neutral point magnetic field due to the magnet equal to `B_(H)`
`B_(H)=(mu_(0))/(4pi).(M)/(OP^(2)+AO^(2))^(3//2)`
`0.4xx10^(3)xx10^(-6)(225)^(3//2)=M`
`M=1.35 A-m`
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