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In H atom the magnitude of magnetic fi...

In H atom the magnitude of magnetic field produced at the centre due ot orbital motion of an e revolving in a orbit of quantum number (n ) is proportional to

A

`(1)/(n^(5))`

B

`(1)/(n^(3))`

C

`n^(3)`

D

n

Text Solution

Verified by Experts

The correct Answer is:
A
`T_(1)=2pisqrt(I)/(M_(1)H),M_(1)=ml,I_(1)=(ml^(2))/(I2)`
`I_(2)=(m)/(3).(l^(2))/(9xx12)xx3 I_(2)=1/9`
`therefore T_(2)=2pisqrt(I)/(9xxMH)=1/3T_(1)=2/3s`
`T_(2)=2/3s`
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