The real angle of dip if a magnet is suspended at an angle of `30^(@)` needle makes and angle of `45^(@)` with horizontal is

Options

A. `tan^(-1)sqr(3)/(2)`
B. `tan^(-1)sqrt(3)`
C. `tan^(-1)sqrt(3)/(2)`
D. `tan^(-1)(2)/sqrt(3)`

Answer

A

Explanation

`because tan delta=(v)/(H)`
`tan 45^(@)=(v)/(H cos 30^(@))`
`delta^(-1)sqrt(3)/(2)`