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If there is no torsion in the suspension...

If there is no torsion in the suspension thread, then the time period of a magnet executing SHM is

A

`T=(1)/(2pi)sqrt(I)/(MB)`

B

`T=2pisqrt(MB)/(I)`

C

`T=(1)/(2pi)sqrt(MB)/(I)`

D

`T=2pisqrt(I)/(MB)`

Text Solution

Verified by Experts

The correct Answer is:
D
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