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If an electron is accelerated by 8.8xx10...

If an electron is accelerated by `8.8xx10^(14)ms^(-2)`, then electric field required for this acceleration is (given specific charge of the electron `=1.76xx10^(11)Ckg^(-1)`):

A

`40Vcm^(-1)`

B

`50Vcm^(-1)`

C

`60Vcm^(-1)`

D

`70Vcm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Electric field `E=(F)/(e)=(ma)/(e)=(a)/((e)/(m))=5xx10^(3)V//m =50 V cm^(-1)`
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