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The photoelectric surface is receiving l...

The photoelectric surface is receiving light of wave length `5000Å` at the rate of `10^(-7)` J/s. The no. of photoelectron received per sec is:

A

`2.5xx10^(12)`

B

`2.5xx10^(11)`

C

`2.5xx10^(10)`

D

`2.5xx10^(9)`

Text Solution

Verified by Experts

The correct Answer is:
B
photns per sec `(10^(-7))/(hc//lambda)=(10^(-7))xx (lambda)/(hc)`
`=(10^(-7)xx5000xx10^(-10))/(6.6xx10^(-34)xx3xx10^(8))`
`=2.5xx10^(11)`
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