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The momentum of a photon of an electron-...

The momentum of a photon of an electron-magnetic radiation is `6.6xx10^(-29)kgms^(-1)`. If `h=6.6xx10^(-34)` js and `c=3xx10^(8)` m/s the frequency of the radiation is

A

`3xx10^(12)Hz`

B

`1.5xx10^(13)Hz`

C

`3xx10^(13)Hz`

D

`1.5xx10^(12)Hz.`

Text Solution

Verified by Experts

The correct Answer is:
C
Since `p=(hv)/(c)`
`v=(pc)/(h)=(6.6xx10^(-29)xx3xx10^(8))/(6.6xx10^(-34))`
`=3xx10^(13)Hz`
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