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The de-Broglie wavelength of neutrons in...

The de-Broglie wavelength of neutrons in thermal equilibrium is :

A

`(30.8)/(sqrtT)Å`

B

`(3.08)/(sqrt(T))Å`

C

`(0.308)/(sqrt(T))Å`

D

`(0.0308)/(sqrt(T))Å`

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda=(h)/(sqrt(3mk//T))=(30*79)/(sqrt(T))Å=(30*8)/(s sqrt(T))Å`
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