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K.E. of free electron doubles, its de-br...

K.E. of free electron doubles, its de-broglie wavelength changes by a factor :

A

`(1)/(sqrt(2))`

B

`sqrt2`

C

`(1)/(2)`

D

2

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda=(12.27)/(sqrt(2mE)) rArr lambda prop (1)/(sqrt(E))`
`lambda. prop (1)/( sqrt(2E))`
`:. (lambda.)/(lambda)=(1)/(sqrt(2)) rArr lambda.=(lambda)/(sqrt(2))`
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