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A charged particle with charge q enters ...

A charged particle with charge q enters a region of constant, uniform and mutually orthogonal fields `vecE` and `vecB` with a velocity `vecv` perpendicular to both `vecE` and `vecB`, and comes out without any change in magnitude or direction of `vecv`. Then

A

`vecv=vecBxxvecE//B^(2)`

B

`vecv=vecExxvecB//E^(2)`

C

`vecv=vecBxxvecE//E^(2)`

D

`vecv=vecExxvecB//B^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`vecv=(vecE xx vecB)/(B^(2))`
`rArr v=(EB sin 90^(@))/(B^(2))`
`:. V=(EB)/(B^(2))=(E)/(B)`
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