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The photoelectric threshold wavelength f...

The photoelectric threshold wavelength for silver in `lambda_(0)`.The energy of the electron ejected from the surface of silver by an incident wavelength `lambda(lambdaltlambda_(0))` will be

A

`hc(lamda_(0)-lamda)`

B

`(hc)/(lamda_(0)-lamda)`

C

`(h)/(c)((lamda_(0)-lamda)/(lamdalamda_(0)))`

D

`hc((lamda_(0)-lamda)/(lamdalamda_(0)))`

Text Solution

Verified by Experts

The correct Answer is:
C
`hc[(1)/(lambda)-(1)/(lambda_(0))]=hcp[(lambda_(0)-lambda)/(lambda lambda_(0))]`
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