An electron of mass `m_(e)` and a proton of mass `m_(p)` are moving with the same speed.The ration of their de-Broglie's wavelengths `(lambda_(e))/(lambda_(p))` is

Options

A. 1
B. 1836
C. `(1)/(1836)`
D. 918

Answer

B

Explanation

de-Broglie.s wavelength,
`lambda=(h)/(mv)`
For electron,
`lambda_(e)=(h)/(m_(e)v)`
for photon
`lambda_(p)=(h)/(m_(p)v)`
`:.(lambda_(e))/(lambda_(p))=(h//m_(e)v)/(h//n_(p)v)`
`(lambda_(e))/(lambdal_(p))=(m_(p))/(m_(e))`
`(lambda_(e))/(lambda_(p))=(1.67xx10^(-27))/(9.1xx10^(-31))`