In hydrogen atom , electron excites from ground state of higher energy state and its orbital velocity is reduced to `((1)/(3))^(rd)` of its initial value . The radius of the orbit in the ground state is R . The radius of the orbit in that higher energy state is ...

Options

A. R 9
B. 2 R
C. 3 R
D. 27 R

Answer

C

Explanation

According to Bohr.s orbit
`mvr=(nh)/(2pi)`
`i.,e v prop (1)/(r),(v_(1))/(v_(2))=(r_(2))/(v_(1))`
`:. (v)/(v//z)=(r_(2))/(R) rArr r_(2)=3R`.