`lamda_(1)` and `lamda_(2)` are used to illuminated the slits. `beta_(1)` and `beta_(2)` are the corresponding fringe widths. The wavelength `lamda_(1)` can produce photoelectric effect when incident on a metal. But the wavelength `lamda_(2)` cannot produce photoelectric effect. The correct relation between `beta_(1)` and `beta_(2)` is

Options

A. `beta_(1)ltbeta_(2)`
B. `beta_(1)=beta_(2)`
C. `beta_(1)gtbeta_(2)`
D. `beta_(1)nebeta_(2)`

Answer

A

Explanation

Fring width `beta prop lambda`. AS given that `lambda_(1)` produced photo electric effect, so `lambda_(1) lt lambda_(2)`
Hence, `beta_(1) lt beta_(2)`