What is the de Broglie wavelength of the electron accelerated through a potential difference of 100 volt ?

Options

A. `12.27Å`
B. `1.227Å`
C. `0.1227Å`
D. `0.001227Å`

Answer

B

Explanation

de-Broglie wavelength of an electron is given by :
`lambda=(h)/(mv)=(h)/(sqrt(2meV))=(12.27)/(sqrt(V))Å`
(h=Plank.s constant)
where m=mass of electron
e= electronic charge and
V= potential difference with which electron is accelerated.
`lambda=(12.27)/(sqrt(100))Å=(12.27)/(10)Å`
`=1.227Å`