Two different isolated coils have self inductances, `L_(1)=8 mH and L_(2) = 2mH`. The current in one coil is increased at a constant rate. The current in second coil is increased at same constant rate. At a certain instant, the power given to two coils is the same. At that time the current, induced voltage and the energy stored in first coil are `i_(1)V_(1) and U_(1)` respectively, Corresponding values for second coil at same instant are `i_(2), V_(2) and U_(2)` respectively. Then,

Options

A. `(i_(1))/(i_(2)) =(1)/(4)`
B. `(i_(1))/(i_(2))=4`
C. `(U_(2))/(U_(1))=(4)/(1)`
D. `(V_(2))/(V_(1))=(1)/(2)`.

Answer

A, C