The equation of the curve whose slope is given by `(dy)/(dx)=(2y)/x ; x >0,\ y >0` and which passes through the point (1,1) is a. `x^2=y` b. `y^2=x` c. `x^2=2y` d. `y^2=2x`

The equation of the curve whose slope is given by (dy)/(dx)=(2y)/(x);x>0,y>0 and which passes through the point (1,1) is x^(2)=yby^(2)=x c.x^(2)=2y d.y^(2)=2x

Find the equation of the curve whose slope is given by dy/dx=(2y)/x and which passes through (1,1).

Find the equation of the curve whose slope is (y-1)/(x^(2)+x) and which passes through the point (1,0).

The equation of the curve,slope of whose tangent at any point (h,k) is (2k)/(h) and which passes through the point (1,1) is (i)x^(2)=y( ii) y^(2)=x( iii) x^(2)=2y( iv )y^(2)=2x

Let y=y(x) be the equation of a curve whose slope at (x,y) is -((x+y))/(x) and which passes through the point (2,1) .Then value of y(1) is

The solution curve of the differential equation, (1+e^(-x))(1+y^(2))(dy)/(dx)=y^(2) , which passes through the point (0,1), is:

The slope at any point of a curve y=f(x) is given by (dy)/(dx)= 2x and it passes through (1,-1) . The equation of the curve is