If x,y and z are eliminated from the equations x=cy+bz, y=az+cx" and z=bx+ay, then `a^(2)+b^(2)+c^(2)+2abc=`

Given x=cy+bz,y=az+cx and z=bx+ay, then prove a^(2) +b^(2) +c^(2) +2abc =1.

If x@+y^(2)+z^(2)!=0,x=cy+bz,y=az+cx, and z=bx+ay, then a^(2)+b^(2)+c^(2)+2abc=

If the planes x=cy+bz,y=az+cx and z=bx+ay pass through a line then a^(2)+b^(2)+c^(2)+2abc is equal to

If x^2+y^2+z^2 ne0, x=cy+bz,y=az+cxandz=bx+ay" then "a^2+b^2+c^2+2abc=

Let a,b,c, be any real number. Suppose that there are real numbers x,y,z not all zero such that x=cy+bz,y=az+cx and z=bx+ay. Then a^(2)+b^(2)+c^(2) +2abc is equal to

If the system of equations x=cy+bzy=az+cxz=bx+ay has a non-trivial solution,show that a^(2)+b^(2)+c^(2)+2abc=1

Consider the linear equations ax +by+cz=0,bx+cy+az=0 and cx+ay+bz=0

The planes x=cy+bz,y=az+cx,z=bx+ay intersect in a line if (a+b+c)^(2) is equal to

The values of x, y, z for the equations x+y+z=1, 2x+3y+2z=2, ax+ay+2az=4 are