From the two systems of line `x-h=0, h=0,1,2,3,4,5` and `y-k=0, k=0,1,2,3` the number of squares that can be formed is

The system of equations 2x+h-5=0, x-2h+1=0,2x-14y-a=0 , is cosistent. Then a is equal to

If the lines x-y-1=0, 4x+3y=k and 2x-3y+1=0 are concurrent, then k is

three lines x+2y+3=0,x+2y-7=0 and 2x-y-4=0 from 3 sides of two squares find the equations of remaining sides of these squares.

The area of the parallelogram formed by the lines 2x-3y+a=0, 3x-2y-a=0, 2x-3y+3a=0 and 3x-2y-2a=0 in square units , is

The orthocentre of triangle formed by lines x+y-1=0, 2x+y-1=0 and y=0 is (h, k), then (1)/(k^(2))=

The sides of a triangle ABC lie on the lines 3x+4y=0,4x+3y=0 and x=3. Let (h,k) be the centre of the circle inscribed in /_ABC. The value of (h+k) equals

If the angle between the lines 3x^(2)-4y^(2)=0 is tan^(-1)k , then k=

If the slopes of the lines 3x^(2) + 2hxy + 4y^(2)=0 are in the ration 3:1 , then h equals

If the image of the point (1,2,3) in the plane x+2y=0 is (h,k,l) then l=